Question
Question: \(\int_{}^{}a^{3x + 3}\)dx =...
∫a3x+3dx =
A
logaa3x+3+c
B
3logaa3x+3+c
C
a3x + 3 log a + c
D
3a3x + 3 log a + c
Answer
3logaa3x+3+c
Explanation
Solution
∫ a3x × a3 dx = a3∫a3xdx =
=
∫a3x+3dx =
logaa3x+3+c
3logaa3x+3+c
a3x + 3 log a + c
3a3x + 3 log a + c
3logaa3x+3+c
∫ a3x × a3 dx = a3∫a3xdx =
=