Question

$\int_{}^{}{(3\text{cose}\text{c}^{2}x + 2\sin 3x)\mspace{6mu} dx =}$ is equal to.

• A. $- \left( 3\cot x + \frac{2}{3}\cos 3x \right) + c$
• B. $3\cot x - \frac{2}{3}\cos 3x + c$
• C. $f'(x) = \frac{1}{x} + x$
• D. $f(1) = \frac{5}{2}$

Answer 1

Answer: (A)

$- \left( 3\cot x + \frac{2}{3}\cos 3x \right) + c$

Answer 2

$x^{2} = t$.