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Question

Question: \(\int_{0}^{\pi}{\sin^{5}\left( \frac{x}{2} \right)dx}\) equals...

0πsin5(x2)dx\int_{0}^{\pi}{\sin^{5}\left( \frac{x}{2} \right)dx} equals

A

1615\frac{16}{15}

B

3215\frac{32}{15}

C

815\frac{8}{15}

D

56\frac{5}{6}

Answer

1615\frac{16}{15}

Explanation

Solution

0πsin52xdx=20π/2sin5tdt=2.Γ62.Γ122Γ72=1615\int_{0}^{\pi}{\sin^{5}\frac{2}{x}dx = 2\int_{0}^{\pi/2}{\sin^{5}tdt = 2.\frac{\Gamma\frac{6}{2}.\Gamma\frac{1}{2}}{2\Gamma\frac{7}{2}} = \frac{16}{15}}}.