Question
Question: \[\int_{0}^{4}{(|x - 1| + 3|x - 2| + 4|x - 3|)dx =}\]...
∫04(∣x−1∣+3∣x−2∣+4∣x−3∣)dx=
A
37
B
14
C
22
D
11
Answer
37
Explanation
Solution
Break integral at x = 1, 2, 3
∫04(∣x−1∣+3∣x−2∣+4∣x−3∣)dx=
37
14
22
11
37
Break integral at x = 1, 2, 3