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Question

Question: \[\int_{0}^{2\pi}{(\sin x + \cos x)dx =}\]...

∫02π(sin⁡x+cos⁡x)dx=\int_{0}^{2\pi}{(\sin x + \cos x)dx =}

A

0

B

2

C

−2- 2

D

1

Answer

0

Explanation

Solution

∫02π(sin⁡x+cos⁡x)dx=[−cos⁡x+sin⁡x]02π=0\int_{0}^{2\pi}{(\sin x + \cos x)dx = \lbrack - \cos x + \sin x\rbrack_{0}^{2\pi} = 0}.