QuestionReportQuestion: \[\int_{0}^{1}{\cos^{- 1}xdx =}\]...∫01cos−1xdx=\int_{0}^{1}{\cos^{- 1}xdx =}∫01cos−1xdx=A0B1C2DNone of theseAnswer1ExplanationSolution∫01cos−1xdx=[xcos−1x−1−x2]01=1{\int_{0}^{1}{\cos^{- 1}xdx = \left\lbrack x\cos^{- 1}x - \sqrt{1 - x^{2}} \right\rbrack}}_{0}^{1} = 1∫01cos−1xdx=[xcos−1x−1−x2]01=1.