Question

$\int_{0}^{1.5}{\lbrack x^{2}\rbrack}$dx =

• A. $\sqrt{2}$
• B. 2 + $\sqrt{2}$
• C. 2 – $\sqrt{2}$
• D. 0

Answer 1

Answer: (C)

2 – $\sqrt{2}$

Answer 2

$\int_{0}^{1}{\lbrack x^{2}\rbrack}$dx + $\int_{1}^{\sqrt{2}}{\lbrack x^{2}\rbrack}$dx+ $\int_{\sqrt{2}}^{1.5}{\lbrack x^{2}\rbrack}$dx

= $\int_{0}^{1}0$dx + $\int_{1}^{\sqrt{2}}{1.dx}$ + $\int_{\sqrt{2}}^{1.5}{2.dx}$

= ($\sqrt{2}$ –1) + 2 (1.5 – $\sqrt{2}$)

= 2 – $\sqrt{2}$