Question
Question: $\int (x+4)^5 dx$...
∫(x+4)5dx
Answer
6(x+4)6+C
Explanation
Solution
Let u=x+4 so that du=dx. The integral becomes:
∫(x+4)5dx=∫u5du=6u6+C=6(x+4)6+C.∫(x+4)5dx
6(x+4)6+C
Let u=x+4 so that du=dx. The integral becomes:
∫(x+4)5dx=∫u5du=6u6+C=6(x+4)6+C.