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Question

Mathematics Question on Integration

∫(tan⁡2(2x)−cot⁡2(2x))dx=\int(\tan^2(2x)-\cot^2(2x))dx=

A

−12(tan⁡2x+cot⁡2x)+C\frac{-1}{2}(\tan2x+\cot2x)+C

B

2(tan2x+cot2x)+C

C

12(tan⁡2x−cot⁡2x)+C\frac{1}{2}(\tan2x-\cot2x)+C

D

−12(tan⁡2x−cot⁡2x)+C\frac{-1}{2}(\tan2x-\cot2x)+C

E

12(tan⁡2x+cot⁡2x)+C\frac{1}{2}(\tan2x+\cot2x)+C

Answer

12(tan⁡2x+cot⁡2x)+C\frac{1}{2}(\tan2x+\cot2x)+C

Explanation

Solution

The correct option is (E) : 12(tan⁡2x+cot⁡2x)+C\frac{1}{2}(\tan2x+\cot2x)+C