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Question

Question: Evaluate the integral: $\int \sqrt{a^{2} -x^{2}} dx$...

Evaluate the integral:

a2x2dx\int \sqrt{a^{2} -x^{2}} dx

Answer

x2a2x2+a22sin1(xa)+C\frac{x}{2}\sqrt{a^{2} -x^{2}} + \frac{a^{2}}{2}\sin^{-1}\left(\frac{x}{a}\right) + C

Explanation

Solution

The integral a2x2dx\int \sqrt{a^{2} -x^{2}} dx is a standard form. The result is obtained by applying the known formula or by using the trigonometric substitution x=asinθx = a \sin \theta, evaluating the resulting integral in terms of θ\theta, and then substituting back to express the result in terms of xx. The constant of integration CC is added as it is an indefinite integral.