Question
Mathematics Question on integral
5∫10(x−1)(x−2)1dx is equal to
A
log3227
B
log2732
C
log98
D
log43
Answer
log2732
Explanation
Solution
Let I=5∫10(x−1)(x−2)1dx =5∫10[x−1−1+x−21]dx =[−log(x−1)+log(x−2)]510 =−log9+log8+log4−log3 =−2log3+3log2+2log2−log3 =−3log3+5log2 =−log27+log32 =log2732