(\integral\limits\_{0}^{\pi}\pi f(\sin,x)dx) is equal to | Mathematics | SolveeIt

$\int\limits_{0}^{\pi}\pi f(\sin\,x)dx$ is equal to

$\pi \int\limits_{0}^{\pi/2} f(\cos\,x)dx$

$\pi \int\limits_{0}^{\pi} f(\cos\,x)dx$

$\pi\int\limits_{0}^{\pi} f(\sin\,x)dx$

$\frac{\pi}{2}\int\limits_{0}^{\pi/2} f(\sin\,x)dx$

Answer

$\pi \int\limits_{0}^{\pi/2} f(\cos\,x)dx$

Explanation

Answer (a) $\pi \int\limits_{0}^{\pi/2} f(\cos\,x)dx$

Mathematics Question on integral