Question
Mathematics Question on Definite Integral
0∫2π1+sinxcosxsinx dx is equal to
A
log 2 -1
B
-log 2
C
log 2
D
1 -log 2
Answer
1 -log 2
Explanation
Solution
The correct answer is (D) : 1 -log 2.
0∫2π1+sinxcosxsinx dx is equal to
log 2 -1
-log 2
log 2
1 -log 2
1 -log 2
The correct answer is (D) : 1 -log 2.