Question
Mathematics Question on Integrals of Some Particular Functions
0∫1000ex−[x]dx is equal to
A
e−1e1000−1
B
1000e1000−1
C
1000e−1
D
1000(e−1)
Answer
1000(e−1)
Explanation
Solution
Let I=0∫1000ex−[x]dx
0∫1000ex−[x]dx is equal to
e−1e1000−1
1000e1000−1
1000e−1
1000(e−1)
1000(e−1)
Let I=0∫1000ex−[x]dx