(\integral\frac{x^2,,,1}{x^4,,,1}dx) | Mathematics | SolveeIt

$\int\frac{x^2\,\,\,1}{x^4\,\,\,1}dx$

$\frac{1}{\sqrt2}log\,e(x^2\,\,\,1)\,\,\,c$

$\frac{1}{\sqrt2}tan\,^1\left(\frac{x^2\,\,\,1}{x\sqrt2}\right)c$

$-\frac{1}{\sqrt2}tan^{-1}(x^2\,-1)+c$

$\frac{1}{\sqrt2}tan\,^{-1}\left(\frac{x^2\,\,\,1}{x\sqrt2}\right)+c$

Answer

$\frac{1}{\sqrt2}tan\,^{-1}\left(\frac{x^2\,\,\,1}{x\sqrt2}\right)+c$

Explanation

Answer (d) $\frac{1}{\sqrt2}tan\,^{-1}\left(\frac{x^2\,\,\,1}{x\sqrt2}\right)+c$

Mathematics Question on Integrals of Some Particular Functions