Question
Mathematics Question on Integration
∫1+sin2xcosx−sinxdx is equal to:
A
sinx+cosx1c, where C is a constant.
B
sinx+cosx−1c, where C is a constant.
C
cosx−sinx1c, where C is a constant.
D
sinx+cosx2c, where C is a constant.
Answer
sinx+cosx−1c, where C is a constant.
Explanation
Solution
The correct option is (B): sinx+cosx−1c, where C is a constant.