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Question

Mathematics Question on Integration

cosxsinx1+sin2xdx\int \frac{cos x - sin x}{1 + sin2x} dx is equal to:

A

1sinx+cosxc\frac{1}{sinx + cosx}c, where C is a constant.

B

1sinx+cosxc\frac{- 1}{sinx + cosx}c, where C is a constant.

C

1cosxsinxc\frac{1}{cos x - sinx}c, where C is a constant.

D

2sinx+cosxc\frac{2}{sinx + cosx}c, where C is a constant.

Answer

1sinx+cosxc\frac{- 1}{sinx + cosx}c, where C is a constant.

Explanation

Solution

The correct option is (B): 1sinx+cosxc\frac{- 1}{sinx + cosx}c, where C is a constant.