(\integral\frac{1}{(1+cot^2x)sin^2x}dx=) | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

$\int\frac{1}{(1+cot^2x)sin^2x}dx=$

A

tan-1(sinx) + C

B

tan-1(cosx) + C

C

cot-1(sinx) + C

D

cos-1(cosx) + C

E

x+C

Answer

x+C

Explanation

Solution

The correct option is (E): x+C