Question
Mathematics Question on integral
∫ex(cosx−sinx)dx is equal to
A
excosx+C
B
exsinx+C
C
−excosx+C
D
−exsinx+C
Answer
excosx+C
Explanation
Solution
Let I=∫ex(cosx−sinx)dx
=∫excosxdx−∫exsinxdx
=∫excosxdx−[ex(−cosx)−∫ex(−cosx)dx]
=∫excosxdx+excosx−∫excosxdx
=excosx+C