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Question

Question: \(\int _ { 1 } ^ { e } \frac { 1 } { x } d x\) is equals to...

∫1e1xdx\int _ { 1 } ^ { e } \frac { 1 } { x } d x is equals to

A

∞\infty

B

0

C

1

D

log⁡(1+e)\log ( 1 + e )

Answer

1

Explanation

Solution

=[log⁡x]1e=log⁡ee−log⁡1=1= [ \log x ] _ { 1 } ^ { e } = \log _ { e } e - \log 1 = 1.