Question
Question: \(\int _ { 0 } ^ { 2 \pi } e ^ { \frac { x } { 2 } } \sin \left( \frac { x } { 2 } + \frac { \pi } {...
∫02πe2xsin(2x+4π) dx =
A
2p
B
ep
C
0
D
22
Answer
0
Explanation
Solution
∫02πex/2{21sin2x+21cos2x} dx
22 dt t = x/2 dx = 2 dt
= 2 [etsint]0π = 2 × 0 = 0