(\integral \_ { 0 } ^ { 1 } ( 1 - x ) ^ { 9 } d x =) | MATH - FUNDAMENTAL DEFINITE INTEGRATION, DEFINITE INTEGRATION BY SUBSTITUTION | SolveeIt

$\int _ { 0 } ^ { 1 } ( 1 - x ) ^ { 9 } d x =$

$\frac { 1 } { 10 }$

$\frac { 11 } { 10 }$

Answer

$\frac { 1 } { 10 }$

Explanation

Required value = $\left[ \frac { - ( 1 - x ) ^ { 10 } } { 10 } \right] _ { 0 } ^ { 1 } = \frac { 1 } { 10 }$ .

Question: \(\int _ { 0 } ^ { 1 } ( 1 - x ) ^ { 9 } d x =\)...