QuestionReportQuestion: $\int 2x\sqrt{1+x^2}dx$...∫2x1+x2dx\int 2x\sqrt{1+x^2}dx∫2x1+x2dxAnswer23(1+x2)32+C\frac{2}{3}(1+x^2)^{\frac{3}{2}} + C32(1+x2)23+CExplanationSolutionSubstitute u=1+x2u=1+x^2u=1+x2 to match du=2x dxdu=2x\,dxdu=2xdx. Integrate u1/2u^{1/2}u1/2 to finish.