Question

Initially the spring is in unstreched condition. Now an electric field (5) is switched on in right direction. The maximum extension in the spring will be – [At max extension condition potential energy of spring = Work done by electric force]

• A. $\frac{2qE}{K}$
• B. $\sqrt{\frac{2qE}{K}}$
• C. $\frac{qE}{K}$
• D. $\sqrt{\frac{qE}{K}}$

Answer 1

Answer: (A)

$\frac{2qE}{K}$

Answer 2

$\frac { 1 } { 2 } \mathrm { kx } ^ { 2 }$= qExŽ x = $\frac { 2 \mathrm { qE } } { \mathrm { k } }$