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Question

Physics Question on Motion in a straight line

Initial velocity of a particle is uu at time t=0t = 0. If acceleration ff of the particle is given by at, then the valid relation is

A

υ=u+at\upsilon=u+at

B

υ=u+12at2\upsilon=u+\frac{1}{2}at^2

C

υ=u+at2\upsilon=u+at^2

D

υ=u\upsilon=u

Answer

υ=u+12at2\upsilon=u+\frac{1}{2}at^2

Explanation

Solution

f=dυdt=atf = \frac{d \upsilon}{dt} = at i.e. dυ=atdtd \, \upsilon = at \, dt υυdυ=0tatdt\int\limits^{\upsilon}_{\upsilon} d \, \upsilon = \int\limits^t_0 \, at \, dt i.e. υu=12at2\upsilon - u = \frac{1}{2} at^2 i.e. υ=u+12at2\upsilon =u + \frac{1}{2} at^2