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Question

Physics Question on Gravitation

Infinite number of masses, each 1kg1 \,kg , are placed along the xaxisx-axis at x=± 1 m,±2m,± 4x=\pm \text{ }1\text{ }m,\pm 2m,\pm \text{ }4 m,± 8 m,± 16m....m,\pm \text{ }8\text{ }m,\pm \text{ }16m.... The magnitude of the resultant gravitational potential in terms of gravitational constant GG at the origin (x=0)(x=0) is

A

G/2G/2

B

GG

C

2G2G

D

4G4G

Answer

2G2G

Explanation

Solution

Gravitational potential
V=GM(1r1+1r2+1r3+......)V=GM\left( \frac{1}{{{r}_{1}}}+\frac{1}{{{r}_{2}}}+\frac{1}{{{r}_{3}}}+...... \right)
=G×1(11+12+14+18+116+....)=G\times 1\left( \frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+.... \right)
=G(111/2)=G\left( \frac{1}{1-1/2} \right)
(sumofGP=a1r)\left( \because sum\,of\,GP=\frac{a}{1-r} \right)