Question

Inequations$3x - y \geq 3$ and $4x - y > 4$

• A. Have solution for positive x and y
• B. Have no solution for positive x and y
• C. Have solution for all x
• D. Have solution for all y

Answer 1

Answer: (A)

Have solution for positive x and y

Answer 2

Following figure will be obtained on drawing the graphs of given inequations:

From $3x - y \geq 3,\frac{x}{1} + \frac{y}{- 3} = 1$

From $4x - y \geq 4,\frac{x}{1} + \frac{y}{- 4} = 1$

Clearly the common region of both the inequations is true for positive value of (x, y).

It is also true for positive values of x and negative values of y.