Question

Inequations $3x - y \geq 3$ and $4x - y \geq 4$

• A. Have solution for positive x and y
• B. Have no solution for positive x and y
• C. Have solution for all x
• D. Have solution for all y

Answer 1

Answer: (A)

Have solution for positive x and y

Answer 2

Following figure will be obtained on drawing the graphs of given inequations. From $3x - y \geq 3, \frac{x}{1} + \frac{y}{-3} = 1$ From $4x - y > 4, \frac{x}{1} + \frac{y}{-4} = 1$ Clearly the common region of both is true for positive value of (x, y). It is also true for positive value of x and negative value of y.