Question
Question: Indicate the expected structure of the organic product when ethyl magnesium bromide is treated wit...
Indicate the expected structure of the organic product when ethyl magnesium bromide is
treated with heavy water (D2O)
Solution
D2O i.e. deuterium oxide, is also known as heavy water. It is a compound made up of deuterium and oxygen.Deuterium is a heavy isotope of hydrogen, denoted by either 2Hor D.
On the other hand, ethyl magnesium bromide is a Grignard reagent.Grignard reagent is basically a chemical compound having the generic formula of R−Mg−X, while, X refers to a halogen and R refers to an organic group, primarily an alkyl or aryl group.
Complete answer: When Grignard reagent (R−Mg−X) is treated with water, it leads to a hydrolysis reaction yielding corresponding alkanes as well as RMg(OH)X. In this reaction, hydrogen of alkane along with hydroxyl group i.e. OH in RMg(OH)X actually comes from water i.e. H2O.
Now in the present question, water (i.e. H2O) is being replaced with heavy water (i.e. D2O). Therefore correspondingly in alkane also, H will be replaced with heavy hydrogen that is D and OH in RMg(OH)X will also get replaced with OD. Thus, the final reaction of ethyl magnesium bromide with heavy water can be written as follows:
C2H5MgBr+D2O→C2H5D+Mg(OD)Br
The structure of the compounds in reaction are also depicted below:
Hence, the expected structure of the organic product i.e. alkane is tetrahedral (since both carbon are sp3 hybridized) when ethyl magnesium bromide is treated with heavy water (D2O).
Therefore, the correct answer is Option D.
Note: Since deuterium’s atomic mass is greater as compared to that of protium (hydrogen), molar mass of D2O is more than that of H2O. Thus, D2O possess slightly different physical and chemical properties in comparison to H2O. D2O is non-radioactive owing to the deuterium being a stable isotope. D2O can also be produced via hydrogen sulfide-water chemical exchange method, electrolysis and water distillation.