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Question: Indicate the expected structure of the organic product when ethyl magnesium bromide is treated wit...

Indicate the expected structure of the organic product when ethyl magnesium bromide is
treated with heavy water (D2O{D_2}O)

{A:{C_2}{H_5} - {C_2}{H_5}} \\\ {B:{C_2}{H_5}OD} \\\ {C:{C_2}{H_6}} \\\ {D:{C_2}{H_5}D} \end{array}$$
Explanation

Solution

D2O{D_2}O i.e. deuterium oxide, is also known as heavy water. It is a compound made up of deuterium and oxygen.Deuterium is a heavy isotope of hydrogen, denoted by either 2H^2Hor DD.
On the other hand, ethyl magnesium bromide is a Grignard reagent.Grignard reagent is basically a chemical compound having the generic formula of RMgXR - Mg - X, while, XX refers to a halogen and R refers to an organic group, primarily an alkyl or aryl group.

Complete answer: When Grignard reagent (RMgXR - Mg - X) is treated with water, it leads to a hydrolysis reaction yielding corresponding alkanes as well as RMg(OH)XRMg\left( {OH} \right)X. In this reaction, hydrogen of alkane along with hydroxyl group i.e. OHOH in RMg(OH)XRMg\left( {OH} \right)X actually comes from water i.e. H2O{H_2}O.
Now in the present question, water (i.e. H2O{H_2}O) is being replaced with heavy water (i.e. D2O{D_2}O). Therefore correspondingly in alkane also, H will be replaced with heavy hydrogen that is DD and OHOH in RMg(OH)XRMg\left( {OH} \right)X will also get replaced with ODOD. Thus, the final reaction of ethyl magnesium bromide with heavy water can be written as follows:

C2H5MgBr+D2OC2H5D+Mg(OD)Br{C_2}{H_5}MgBr + {D_2}O \to {C_2}{H_5}D + Mg\left( {OD} \right)Br

The structure of the compounds in reaction are also depicted below:

Hence, the expected structure of the organic product i.e. alkane is tetrahedral (since both carbon are sp3 hybridized) when ethyl magnesium bromide is treated with heavy water (D2O{D_2}O).

Therefore, the correct answer is Option D.

Note: Since deuterium’s atomic mass is greater as compared to that of protium (hydrogen), molar mass of D2O{D_2}O is more than that of H2O{H_2}O. Thus, D2O{D_2}O possess slightly different physical and chemical properties in comparison to H2O{H_2}O. D2O{D_2}O is non-radioactive owing to the deuterium being a stable isotope. D2O{D_2}O can also be produced via hydrogen sulfide-water chemical exchange method, electrolysis and water distillation.