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Question

Physics Question on Current electricity

Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature. If at room temperature, 100W,60W100\, W, 60\, W and 40W40\, W bulbs have filament resistances R100,R60R_{100}, R_{60} and R40,R_{40}, respectively, the relation between these resistances is

A

1R100=1R40+1R60\frac{1}{R_{100}} = \frac{1}{R_{40}} + \frac{1}{R_{60}}

B

R100=R40+R60R_{100} = R_{40} + R_{60}

C

R100>R60>R40R_{100} > R_{60} > R_{40}

D

1R100>1R60>1R40\frac{1}{R_{100}} > \frac{1}{R_{60}} > \frac{1}{R_{40}}

Answer

1R100>1R60>1R40\frac{1}{R_{100}} > \frac{1}{R_{60}} > \frac{1}{R_{40}}

Explanation

Solution

R=V2PorR?1PR = \frac{V^2}{P} \, or \, R ? \frac{1}{P}
1R100>1R60>1R40\therefore \, \, \, \, \, \, \, \frac{1}{R_{100}} > \frac{1}{R_{60}} > \frac{1}{R_{40}}
Hence, the correct option is (d).