Question

In Young’s double slit experiment, the 10^th maximum of wavelength $\lambda_{1}$is at a distance $y_{1}$from its central maximum and the 5^th maximum of wavelength $\lambda_{2}$is at a distance $y_{2}$from its central maximum. the ratio $\frac{y_{1}}{y_{2}}$will be:

• A. $\frac{2\lambda_{1}}{\lambda_{2}}$
• B. $\frac{2\lambda_{1}}{\lambda_{1}}$
• C. $\frac{\lambda_{1}}{2\lambda_{2}}$
• D. $\frac{\lambda_{1}}{2\lambda_{1}}$

Answer 1

Answer: (A)

$\frac{2\lambda_{1}}{\lambda_{2}}$

Answer 2

: We know that$y_{m} = \frac{m\lambda D}{d}$

Therefore for wavelength $y_{1} = \frac{10\lambda_{1}D}{d}$

And for wavelength $\lambda_{2},$

$y_{2} = \frac{5\lambda_{2}D}{d},\therefore\frac{y_{1}}{y_{2}} = \frac{2\lambda_{1}}{\lambda_{2}}$