Question

In Young's double slit experiment, if the slit widths are in the ratio 1 : 9, then the ratio of the intensity at minima to that at maxima will be.

• A. 1
• B. 1/9
• C. 1/4
• D. 1/3

Answer 1

Answer: (C)

1/4

Answer 2

Slit width ratio = 1 : 9

Since slit width ratio is the ratio of intensity and intensity$\propto$ (amplitude)²

$\therefore I_{1}:I_{2} = 1:9$

$\Rightarrow a_{1}^{2}:a_{2}^{2} = 1:9 \Rightarrow a_{1}:a_{2} = 1:3$

${I{{1_{2}}^{2}{1_{2}}^{2}\frac{I_{\min}}{I_{\max} = \frac{1}{4}}}_{\min}}_{\max}$