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Question

Physics Question on Youngs double slit experiment

In Youngs double slit experiment, a mica slit of thickness t and refractive index μ\mu is introduced in the ray from the first source S1.{{S}_{1.}} . By how much distance the fringes pattern will be displaced?

A

Dd(μ1)\frac{D}{d}(\mu -1)

B

d(μ1)D\frac{d}{(\mu -1)D}

C

Dd(μ1)t\frac{D}{d}(\mu -1)t

D

dD(μ1)t\frac{d}{D}(\mu -1)t

Answer

Dd(μ1)t\frac{D}{d}(\mu -1)t

Explanation

Solution

Path difference yp=Dd{{y}_{p}}=\frac{D}{d} Now additional path difference is (μ1)t(\mu -1)t . Therefore displacement will be Δy=Dd(μ1)t\Delta y=\frac{D}{d}(\mu -1)\,t