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Question

Physics Question on Youngs double slit experiment

In Young's double slits experiment, the position of 5th 5^{\text {th }} bright fringe from the central maximum is 5cm5 \,cm The distance between slits and screen is 1m1 \,m and wavelength of used monochromatic light is 600mm600 \,mm The separation between the slits is:

A

12μm12\, \mu m

B

60μm60\, \mu m

C

36μm36\, \mu m

D

48μm48 \,\mu m

Answer

48μm48 \,\mu m

Explanation

Solution

Given
D=1m
λ=600×10−9m
n=5
As ynth​=dnλD​
⇒d5×600×10−9×1​=5×10−2
⇒d=5×10−25×600×10−9×1​=60×10−6m
⇒d=60μm