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Physics Question on Youngs double slit experiment

In Young's double slit experiment, two slits S1S_1 and S2S_2 are ' dd ' distance apart and the separation from slits to screen is DD (as shown in figure) Now if two transparent slabs of equal thickness 0.1mm0.1 \,mm but refractive index 1.511.51 and 1.551.55 are introduced in the path of beam (λ=4000A˚)(\lambda=4000 \mathring {A}) from S1S_1 and S2S_2 respectively, The central bright fringe spot will shift by ______number of fringes
Young's double slit experiment, two slits S1 and S2 are ' d ' distance apart and the separation from slits to screen is D

Answer

The correct answer is 10.
Young's double slit experiment, two slits S1 and S2 are ' d ' distance apart and the separation from slits to screen is D

Path difference at P be Δx
Δx=(μ2​−μ1​)t
=(1.55−1.51)0.1mm
=0.04×10−4
Δx=4×10−6=4μm
y=dΔxD​=4×10−6dD​
{y is the distance of central maxima from geometric center }
(β) fringe width ​=dλD​=4×10−6mdD​=4μmdD​
∴ Central bright fringe spot will shift by ' x '
Number of shift =βy​
=4×10−7D/d4×10−6D/d​=10