Question

In Young's double slit experiment, slit separation is $0.6 \,mm$ and the separation between slit and screen is $1.2\, m$. The angular width is (the wavelength of light used is $4800\,?$

• A. $30$ rad
• B. $8\times 10^{-4}$ rad
• C. $12$ rad
• D. $70.5$ rad

Answer 1

Answer: (B)

$8\times 10^{-4}$ rad

Answer 2

Angular width $\theta=\frac{\beta}{D}$ $=\frac{\lambda}{d}=\frac{4800 \times 10^{-10}}{0.6 \times 10^{-3}}$ $=8 \times 10^{-4}$ rad