Question
Physics Question on Youngs double slit experiment
In Young's double slit experiment performed using a monochromatic light of wavelength λ, when a glass plate (μ = 1.5) of thickness xλ is introduced in the path of the one of the interfering beams, the intensity at the position where the central maximum occurred previously remains unchanged. The value of x will be:
A
3
B
2
C
1.5
D
0.5
Answer
2
Explanation
Solution
The correct answer is (B) : 2
For the intensity to remain same the position must be of a maxima so path difference must be nλ so
(1.5 – 1)xλ = nλ
x = 2n (n = 0, 1, 2 …)
So, value of x will be
x = 0, 2, 4, 6…