Solveeit Logo

Question

Physics Question on Wave optics

In Young's double slit experiment, intensity at a bright fringe is I0I_0. One of the slits is closed. Intensity at the same position is

A

I02\frac{I_0}{2}

B

I0I_0

C

I04\frac{I_0}{4}

D

zero

Answer

I04\frac{I_0}{4}

Explanation

Solution

Intensity of the bright fringe = I0I_0
We know, maximum intensity of a bright fringe
I0=4×I_0 = 4 \times Intensity of ligh,t through one slit
\therefore Intensity of light through one slit = I04\frac{I_0}{4}
Intensity at the point of bright fringe.