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Question

Physics Question on Wave optics

In Young's double slit experiment,1st1^{st} dark fringe occurs directly opposite a slit. Wavelength of light used is

A

d2D\frac{d^2}{D}

B

dD\frac{d}{D}

C

D2d\frac{D^2}{d}

D

2d2D\frac{2d^2}{D}

Answer

d2D\frac{d^2}{D}

Explanation

Solution

Condition for dark fringes
Δx=(n+12)λ\Delta x = \left(n + \frac{1}{2}\right)\lambda
Also, Δx=dtanθ=dtanθ=dyΔ\Delta x=d \tan \theta = d \tan\theta = d \frac{y }{\Delta }
dyD=(n+12)λ\therefore \, d \frac{y}{D} = \left(n +\frac{1}{2}\right)\lambda
For n=0,Y=d2n =0, Y = \frac{d}{2}
.d.(d2)D=λ2or,λ=d2D. \Rightarrow \frac{d . \left(\frac{d}{2}\right)}{D} = \frac{\lambda}{2} or, \lambda = \frac{d^{2}}{D}