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Question

Physics Question on Wave optics

In Young?? double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

A

Sin−1(0.1)Sin^{-1} (0.1 )

B

Sin−1(0.001)Sin^{-1} (0.001 )

C

Sin−1(0.0001)Sin^{-1} (0.0001 )

D

Sin−1(0.01)Sin^{-1} (0.01 )

Answer

Sin−1(0.001)Sin^{-1} (0.001 )

Explanation

Solution

In Young?? double slit experiment half angular width is given by sin θ=λdsin \, \theta = \frac{\lambda}{d} =589×10−30.589×10−3=10−3= \frac{589 \times10 ^{-3}}{0.589 \times10 ^{-3}} = 10 ^{-3} ⇒θ=sin−1(0.001)\Rightarrow \theta = sin ^{-1 \left(0.001\right)}