Question

In $XeOF_{2}$ molecule, the hybridisation of $Xe$ orbitals is

• A. $sp^{3}d^{3}$
• B. $sp^{3}d^{2}$
• C. $sp^{3}d$
• D. $sp^{3}$

Answer 1

Answer: (C)

$sp^{3}d$

Answer 2

In $XeOF _{2}$ molecule $Xe$ is $s p^{3} d$ hybridised. It has $3 bp$ and $2 l p$.