Question

In Wolff-Kishner reduction, the carbonyl group of aldehydes and ketones is converted into

• A. $-CH_2OH$
• B. $> CH_2$
• C. $-CH_3$
• D. $-CHOH-$

Answer 1

Answer: (B)

$> CH_2$

Answer 2

Wolf - Kishner reduction : Aldehyde and Ketones are reduced to hydrocarbons in the presence of excess of hydrazine and strong base on heating. $R - \underset{\underset{H}{|}}{C} = O + H _{2} N NH _{2} {->[{ KOH }][{200^{\circ} C }]} R - \underset{\underset{H}{|}}{C}H _{2}+ N _{2}+ H _{2} O$