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Chemistry Question on Redox reactions

In which of the following reactions H2O2H_2O_2 acts as a reducing agent? (a) H2O2+2H++2e−→2H2OH_2O_2 + 2H^+ + 2e^- \rightarrow 2H_2O (d) H2O2−2e−→O2+2H+H_2O_2 - 2e^- \rightarrow O_2 + 2H^+ (c) H2O2+2e−→2OH−H_2O_2 + 2e^- \rightarrow 2OH^- (d) H2O2+2OH−−2e−→O2+2H2OH_2O_2 + 2OH^- - 2e^- \rightarrow O_2 + 2H_2O

A

(a) and (b)

B

(c) and (d)

C

(a) and (c)

D

(b) and (d)

Answer

(b) and (d)

Explanation

Solution

The reducing agent oxidises itself.

(a) H2O2−1+2H++2e−⟶2H2O−2H _{2} O _{2}^{-1}+2 H ^{+}+2 e ^{-} \longrightarrow 2 H _{2} O ^{-2}

(b) H2O2−1−2e⟶O2+2H+H _{2} O _{2}^{-1}-2 e \longrightarrow O _{2}+2 H ^{+}

(c) H2O2−1+2e⟶2OH−2H _{2} O _{2}^{-1}+2 e \longrightarrow 2 OH ^{-2}

(d) H2O2−1+2OH−−2e⟶O2+H2OH _{2} O _{2}^{-1}+2 OH ^{-}-2 e \longrightarrow O _{2}+ H _{2} O

Note: Powers of 'O' are oxidation number of 'O' in the compound.