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Chemistry Question on Nuclear physics

In which of the following nuclear reaction X and Y are isotopes?

A

X(α, p)YX(\alpha ,\text{ }p)Y

B

X(α, n)YX(\alpha ,\text{ n})Y

C

X(p, n)YX(p,\text{ n})Y

D

X(d, p)YX(d,\text{ p})Y

Answer

X(d, p)YX(d,\text{ p})Y

Explanation

Solution

Isotopes are the species having same atomic number and different atomic mass. aXb+2He4α−article →1H1proton +a+1Yb+3(α,p type)_{a}{{X}^{b}}+\underset{\alpha -article}{\mathop{_{2}H{{e}^{4}}}}\,\to \underset{proton}{\mathop{_{1}{{H}^{1}}}}\,{{+}_{a+1}}{{Y}^{b+3}}(\alpha ,p\,type) aXb+2He4α−article →0n1neutron +a+2Yb+3(α,n type)_{a}{{X}^{b}}+\underset{\alpha -article}{\mathop{_{2}H{{e}^{4}}}}\,\to \underset{neutron}{\mathop{_{0}{{n}^{1}}}}\,{{+}_{a+2}}{{Y}^{b+3}}(\alpha ,n\,type) aXb+1H1proton →0n1neutron +a+1Yb(p,n type)_{a}{{X}^{b}}+\underset{proton}{\mathop{_{1}{{H}^{1}}}}\,\to \underset{neutron}{\mathop{_{0}{{n}^{1}}}}\,{{+}_{a+1}}{{Y}^{b}}(p,n\,type) aXb+1H1deutron →1H1proton +aYb+1(d,p  type)_{a}{{X}^{b}}+\underset{deutron}{\mathop{_{1}{{H}^{1}}}}\,\to \underset{proton}{\mathop{_{1}{{H}^{1}}}}\,{{+}_{a}}{{Y}^{b+1}}(d,p\,\,type) Only in option XX and Y have same atomic number and different atomic mass, hence XX and Y are isotopes in nuclear reaction given in option .