Question

In which of the following molecules $S$ atom does not assume $sp ^{3}$ hybridsation?

• A. $SO_4^{2-}$
• B. $SF_4$
• C. $SF_2$
• D. $SF_8$

Answer 1

Answer: (B)

$SF_4$

Answer 2

In $SO _{4}^{2-} \Rightarrow bp =4, lp =0$
$\therefore$ hybridisation $sp ^{3}$
In SF $_{4} \Rightarrow bp =4, lp =1$
$\therefore$ hybridisation $sp ^{3} d$
In $SF _{2} \Rightarrow bp =2, lp =2$
$\therefore$ hybridisation $sp ^{3}$
In $S _{8} \Rightarrow bp =2, lp =2$
$\therefore$ hybridisation $sp ^{3}$
Thus, only $SF _{4}$ does not have $sp ^{3}$ hybridisation.