Question

In which of the following compounds, nitrogen exhibits highest oxidation state ?

• A. $N_3H$
• B. $NH_2OH$
• C. $N_2H_4$
• D. $NH_3$

Answer 1

Answer: (A)

$N_3H$

Answer 2

Oxidation number of nitrogen $- N _{3} H =-1 / 3,$
$NH _{2} OH =-1,$
$N _{2} H _{4}=-2,$
$NH _{3}= -3$