Question

In which of the following compounds carbon is in highest oxidation state?

• A. $CH_{3}Cl$
• B. $CCl_{4}$
• C. $CHCl_{3}$
• D. $CH_{2}Cl_{2}$

Answer 1

Answer: (B)

$CCl_{4}$

Answer 2

: $CH_{3}Cl:x + 3 - 1 = 0 \Rightarrow x = - 2$

$CCl_{4}:x - 4 = 0 \Rightarrow x = + 4$

$CHCl_{3}:x + 1 - 3 = 0 \Rightarrow x = + 2$

$CH_{2}Cl_{2}:x + 2 - 2 = 0 \Rightarrow x = 0$