Question

In which of the following compound has only one type of hybridized carbon atom
a.
b.
c.
d. Any of these

Answer 1

Carbon has only three types of hybridization. These are $sp,s{p^2}$ and $s{p^3}$. Since there are only three hybridizations for carbon, check all the carbon atoms hybridization one by one then we will get our desired solution.

Complete step by step solution: Carbon atoms form bonds using different orbitals and it can contribute to the formation of different structures and properties.
Here, we have three different cyclic hydrocarbons. We know that if one carbon atom has all single bond then it has $\;s{p^3}$ hybridization, If the carbon atom has one double bond then it has $s{p^2}$ hybridization and if the carbon atom has one triple bond then it has $sp$ hybridization.
Here when we look at the images all of the cyclic hydrocarbons has either a single bond or double bond.

(1) Lets, look at the first image. It has two double bonds. But the top part carbon atom does not have any double bond attached to it. Therefore that $C - atom$ becomes $s{p^3}$. Rest of the four $C - atom$ has double bonds attached to it therefore they all have $s{p^2}$ hybridization.

(2) When we look at the second images, it has four $C - atom$ and two double bonds. All $C - atom$ is attached to double bonds. Therefore, all the four $C - atom$ has $s{p^2}$ hybridization. i.e., all the $C - atom$ has same type of hybridization.

(3) Coming to the third image, it is a cyclic hydrocarbon with 6 carbon atoms and has 2 double bonds. Four of the carbon atoms have double bonds attached to it and two of them have only a single bond. Therefore this has two different type of hybridization $s{p^2}$ and $s{p^3}$

**Therefore, option(a) is correct

Note:**
Since carbon does not have any lone pairs, we are not considering that here. But always try to remember to add the lone pairs of the atom to find the hybridization.