Question
Question: In which of the following circuits the maximum power dissipation is observed? \(\left( {\text{A}} ...
In which of the following circuits the maximum power dissipation is observed?
(A) Pure capacitive circuit
(B) Pure inductive circuit
(C) Pure resistive circuit
(D) None of these
Solution
Power dissipation: It is defined as the rate at which energy is lost due to resistive elements in the circuit.
Power: It is the amount of work done per unit time.
If we know the voltage drop across a component and the current through it, we can calculate the power dissipation by using Ohm’s law.
Formula used:
By using Ohm’s law, V = IR, hereV= Potential difference across the circuit, I= current flowing in the circuit,
R= Resistance of the circuit.
Power dissipation,P = VrmsIrmscosϕ, here Vrms= RMS voltage difference across the circuit,
Irms= RMS current flow in the circuit, ϕ= phase difference between the current and the voltage
Complete step by step answer:
In a purely resistive and capacitive circuit, the phase difference is 90∘-,
By substituting the values of ϕ in the equation we get,
P = VrmsIrmscosϕ
=VrmsIrmscos900=0, as we know that the value of cos900=0
But in a purely resistive circuit, the voltage and current are in the same phase so phase difference is zero. Therefore, it will have maximum power dissipation when, cosϕ = 1, that means ϕ=00.
Hence, the correct option is (C).
Note:
RMS voltage: It is the square root of the mean value of the square function of the instantaneous values of potential difference or the voltage.
RMS current: It is the square root of the mean value of the square function of the instantaneous values of current.
The pure capacitive circuits only contain a capacitor in the circuit.
The pure inductive circuits only contain an inductor in the circuit.
The pure resistive circuits only contain a resistor in the circuit.