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Question: In which direction should a motorboat head in order to reach a point on the opposite bank directly e...

In which direction should a motorboat head in order to reach a point on the opposite bank directly east from the starting point? (The boat's speed relative to the water remains 4ms14m{{s}^{-1}}, velocity of river relative to ground is 2ms12m{{s}^{-1}})

Explanation

Solution

As motor boats have to reach at the exact opposite end of the river it will have to move somewhat opposite to the direction of flow of the river. The component of velocity along the direction opposite to flow of the river must be zero. This condition can be used to obtain the direction a motorboat should head to reach at an exactly opposite point.

Complete step-by-step answer:
As motor boats have to reach at the exact opposite end of the river it will have to move somewhat opposite to the direction of flow of the river. Let us assume that the motor boat has to head at an angle θ\theta with the direction opposite to the flow of the water. The boat is moving with a velocity of 4ms14m{{s}^{-1}} with respect to that of water.

Relative velocity of a body is defined as the velocity of that body with reference to some other body assumed to be at rest. Here, the relative velocity of the motor boat is given with respect to water. That is,
vb,w=vb,gvw,g{{v}_{b,w}}={{v}_{b,g}}-{{v}_{w,g}}
Where vb,w{{v}_{b,w}}, vb,g{{v}_{b,g}} and vw,g{{v}_{w,g}} are velocity of boat with respect to water, velocity of boat with respect to ground and velocity of water relative to ground respectively.
Since motor boats have to reach at the exact opposite end of the river, its component parallel to flow of water is equal to velocity of water with respect to ground in magnitude but opposite in direction. Therefore, vb,wcosθ=vw,g{{v}_{b,w}}\cos \theta ={{v}_{w,g}}
Given that, vb,w=4m/s{{v}_{b,w}}=4m/s and vw,g=2m/s{{v}_{w,g}}=2m/s. Substituting these values, we have
4cosθ=24\cos \theta =2
This implies that,
cosθ=12\cos \theta =\dfrac{1}{2}
We know that, cosθ=12\cos \theta =\dfrac{1}{2} for θ=60\theta ={{60}^{{}^\circ }}
Hence, the motorboat should head in 60{{60}^{{}^\circ }} east of north.

So, the correct answer is “Option A”.

Note: Velocity is a vector quantity and has both magnitude and direction.
The relative velocity of an object A with respect to B is defined as its velocity in the rest frame of object B.
For a motor boat to reach at the exact opposite end of the river it will have to move somewhat aiming to opposite the direction of flow of the river.