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Chemistry Question on Some basic concepts of chemistry

In which case is the number of molecules of water maximum ?

A

10−310^{-3} mol of water

B

18 mL of water

C

0.00224 L of water vapours at 1 atm and 273 K

D

0.18 g of water

Answer

18 mL of water

Explanation

Solution

(1) Molecules of water == mole ×NA=10−3 NA\times N_{A}=10^{-3} \,N_{A}

(2) Mass of water =18×1=18 g=18 \times 1=18 \,g

Molecules of water == mole ×NA=1818 NA\times N_{A}=\frac{18}{18} \,N_{A}
=NA=N_{A}

(3)Moles of water =0.0022422.4= 10−4=\frac{0.00224}{22.4}=\,10^{-4}

Molecules of water == mole ×NA=10−4 NA\times N_{A}=10^{-4} \,N_{A}

(4) Molecules of water == mole ×NA=0.1818NA\times N_{A}=\frac{0.18}{18} N _{A}
=10−2 NA=10^{-2} \,N _{ A }